(x^1/3+z^2/3y^1/3)(x^2/5+z^3/4y^1/3)

Solution for (x^1/3+z^2/3y^1/3)(x^2/5+z^3/4y^1/3) equation:

x in (-oo:+oo)

((x^1)/3+(y^1*((z^2)/3))/3)*((x^2)/5+(y^1*((z^3)/4))/3) = 0

(x/3+(y*((z^2)/3))/3)*((x^2)/5+(y*((z^3)/4))/3) = 0

(1/3*x+1/9*y*z^2)*(1/5*x^2+1/12*y*z^3) = 0

( 1/3*x+1/9*y*z^2 )

1/3*x+1/9*y*z^2 = 0 // - 1/9*y*z^2

1/3*x = -(1/9*y*z^2) // : 1/3

x = (-(1/9*y*z^2))/1/3

x = -1/3*y*z^2

( 1/5*x^2+1/12*y*z^3 )

1/5*x^2 = -(1/12*y*z^3) // : 1/5

x^2 = -5/12*y*z^3

x^2 = -5/12*y*z^3 // ^ 1/2

abs(x) = (-5/12)^(1/2)*y^(1/2)*z^(3/2)

x = (-5/12)^(1/2)*y^(1/2)*z^(3/2) or x = -((-5/12)^(1/2)*y^(1/2)*z^(3/2))

x in { -1/3*y*z^2, (-5/12)^(1/2)*y^(1/2)*z^(3/2), -((-5/12)^(1/2)*y^(1/2)*z^(3/2)) }